spec bug in dfdl:hexBinary function example
In discussion of the dfdl:hexBinary function, it says literals are given the smallest signed type that will hold them. This example is therefore incorrect: • dfdl:hexBinary(208) is the hexBinary value "D0". EXB Should be value 00D0 since 208 is beyond the range of a signed byte, so must be a signed short. Mike Beckerle | OGF DFDL Workgroup Co-Chair | Tresys Technology | www.tresys.com Please note: Contributions to the DFDL Workgroup's email discussions are subject to the OGF Intellectual Property Policy http://www.ogf.org/About/abt_policies.php
Tracked by issue http://redmine.ogf.org/issues/232.
See suggested change to the other '208' example.
Regards
Steve Hanson
Architect, IBM DFDL
Co-Chair, OGF DFDL Working Group
IBM SWG, Hursley, UK
smh@uk.ibm.com
tel:+44-1962-815848
From: Mike Beckerle
participants (2)
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Mike Beckerle
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Steve Hanson