In discussion of the dfdl:hexBinary function, it says literals are given the smallest signed type that will hold them.

This example is therefore incorrect:

• dfdl:hexBinary(208) is the hexBinary value "D0". EXB

Should be value 00D0 since 208 is beyond the range of a signed byte, so must be a signed short.

Mike Beckerle | OGF DFDL Workgroup Co-Chair | Tresys Technology | www.tresys.com

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