I'm pretty sure that the rules are: - DFDL expressions must not *contain* DFDL String Literals. They must be valid XPath 2.0 expressions except that the list of allowable function names includes the DFDL extension functions. - A DFDL expression is sometimes allowed to *return* a DFDL String Literal. In this case, the returned value is an xs:string that conforms to the DFDL String Literal syntax. But that does not apply to your example because the dfdl:inputValueCalc must return a value ( an XML value ) that is valid for the type of the element. I think that corresponds to your answer a) ; 'DEADBEEF' is a valid xs:hexBinary lexical value. regards, Tim Kimber, Common Transformation Team, Hursley, UK Internet: kimbert@uk.ibm.com Tel. 01962-816742 Internal tel. 246742 From: Mike Beckerle <mbeckerle.dfdl@gmail.com> To: Steve Hanson/UK/IBM@IBMGB Cc: dfdl-wg@ogf.org Date: 19/04/2012 07:42 Subject: [DFDL-WG] String literal syntax for hexBinary ?? - Re: String literals - various usage patterns thereof Sent by: dfdl-wg-bounces@ogf.org What is the DFDL string literal syntax for a hexBinary type value? E.g., I want a hex binary whose value is the 4 bytes described by this hex: DE AD BE EF. <element name="myHexBin" type="xs:hexBinary" dfdl:inputValueCalc="{ ... }"/> So, what can one syntactically put, for literal constant values, in the input value calculation expression? Note that this is legal pure (non-DFDL) XSD (I think) <element name="aHexBin" type="xs:hexBinary" fixed="DeadBeef"/> That is, the fixed/default are allowed and one specifies these values as just strings of hex digits. Notice no special escaping or anything. You just use a string that just so happens to contain hex digits. I think there are three possibilites (a) we allow "DEADBEEF" i.e., because the type of the expression is hexBinary, a string is cast to hexBinary by interpreting it as hex nibbles. (b) we require a special kind of string literal - a bytes-only string literal, so for example: "%#rDE;%#rAD;%#rBE;%#rEF;" is the way you create 4 bytes. If you just put characters, then that's a processing error - like a cast failure. Only raw-bytes allowed. (c) Anything you return from the expression is converted to a hexBinary by unparsing it to bytes (using current properties), then using the bytes as the hexBinary data. So you could have an expression that returns a double, and that would create 8 bytes if representation="binary". In this case the decimal number 3735928559 (hex 0xdeadbeef) as a binary bigEndian int would produce the 4 bytes I want. -- dfdl-wg mailing list dfdl-wg@ogf.org https://www.ogf.org/mailman/listinfo/dfdl-wg Unless stated otherwise above: IBM United Kingdom Limited - Registered in England and Wales with number 741598. Registered office: PO Box 41, North Harbour, Portsmouth, Hampshire PO6 3AU