Hi Mike
That looks pretty good. A couple of minor changes in bold red (I don't
think there's a length() function).
Regards
Steve Hanson
Architect, Data Format Description Language (DFDL)
Co-Chair, OGF DFDL Working Group
IBM SWG, Hursley, UK
smh@uk.ibm.com
tel:+44-1962-815848
From:
"Mike Beckerle"
To:
Steve Hanson/UK/IBM@IBMGB, "'Ryan Farrell'"
Cc:
Date:
26/07/2011 18:04
Subject:
RE: [DFDL-WG] [wg-all] Repeating groups in DFDL
From our call today, I suggest this schema, based on the assertion
suggestion from steve/tim, and adding in the unparser/output direction
calculations, and putting this together to match Ryan’s example schema.
I’m not certain on the xpath expressions syntax. I may have number of “..”
moves wrong (at least).
I added outputValueCalc properties to the flag bits, I added
occursCountKind=’parsed’ to the array, and the assertion to the repeatBit
element. I put in the check so that a zero length array is possible based
on the presentBit as well.
xs:complexType
xs:sequence
xs:complexType
xs:sequence
xs:annotation
dfdl:assert{
if ../../presentBit eq
0
then false
else if
dfdl:position() eq 1
then true
else if
../[dfdl:position()-1]/repeatBit eq 0
then false
else true
}
From: Steve Hanson [mailto:smh@uk.ibm.com]
Sent: Tuesday, July 26, 2011 6:40 AM
To: Mike Beckerle
Cc: dfdl-wg@ogf.org; 'Ryan Farrell'
Subject: Re: [DFDL-WG] [wg-all] Repeating groups in DFDL
Yes we need a friendly way of saying 'I am the last item' when using
occursCountKind is 'parsed'.
But with what we have today, could we use a discriminator on the repeating
element that fails when the indicator of the previous repeat was 0 ? So
speculation starts to parse the thing after the last repeat on the
assumption it is another repeat and then fails and backtracks.
dfdl:assert{if dfdl:position() eq 1 then true else if
'./present[dfdl:position()-1]' eq 0 then false else true}
Regards
Steve Hanson
Architect, Data Format Description Language (DFDL)
Co-Chair, OGF DFDL Working Group
IBM SWG, Hursley, UK
smh@uk.ibm.com
tel:+44-1962-815848
From:
"Mike Beckerle"
To:
"'Ryan Farrell'" ,
Date:
22/07/2011 23:44
Subject:
Re: [DFDL-WG] [wg-all] Repeating groups in DFDL
Sent by:
dfdl-wg-bounces@ogf.org
Great example Ryan,
We've spent quite a bit of time over the last several months on textual
formats with these kinds of characteristics, which I would describe as
"occurrances determined by parsing" - that is, you look at the data to
determine "is there another element or not" one by one as they are parsed.
We need to make sure the properties are there to make this work for the
binary case as well.
I actually believe we cannot handle this format right now. We don't have a
property which says to look at the current element to determine whether to
expect a subsequent element, as a way of determining occurrence counts.
Next week we'll add resolving this example to the workgroup actions list.
...mikeb
Mike Beckerle
Senior Technology Leader/Manager
Deloitte Managed Analytics
100 Fifth Avenue, Waltham, MA 02451
Tel/Direct: +1 781 330 0412 | Fax: +1 866 253 3006
www.deloitte.com
-----Original Message-----
From: dfdl-wg-bounces@ogf.org [mailto:dfdl-wg-bounces@ogf.org] On Behalf
Of
Ryan Farrell
Sent: Tuesday, July 19, 2011 2:12 PM
To: dfdl-wg@ogf.org
Subject: [DFDL-WG] [wg-all] Repeating groups in DFDL
For anyone that was at the 19/07 phone meeting, this is what Adam Fox
and I were trying to find a solution to. If anyone knows of a solution,
please contact me or adam.fox@nrl.navy.mil.
----------------------------------------------------------------------------
------------------------
Please see the attached xml schema while reading this message.
The problem we want to solve is how to represent a structure that can
have a variable amount of occurences (even zero), and the amount of
repeats is controlled by a one bit field, which we will call"repeatBit".
The repeating structure in this case is "A1". The element before it,
"presentBit", determines if there is at least one occurence of A1. If
presentBit is zero, then A1 has zero occurences. If presentBit is one,
then A1 has AT LEAST one occurence.
The first element in A1 is "repeatBit". What repeatBit does is tells us
if there will be another occurence of A1 after the current occurence.
When repeatBit is zero, then that means we will read through the rest of
A1, then that is the last occurence of A1. As long as repeatBit
continues to be one however, we will read through the rest of A1, then
start a new occurence.
I have included all the known required DFDL notation. Please let me know
what is missing.
EXAMPLE INPUT (results are in base 10):
NOTE: Not all bits are used in these examples. Unused bits
should be ignored for the purpose of the examples.
1) 0111 0101
presentBit = 0
aFieldAfterA1 = 3
2) 1011 1010
presentBit = 1
A1
-repeatBit = 0
-someField = 3
aFieldAfterA1 = 2
3) 1101 0110 0000 0000
presentBit = 1
A1
-repeatBit = 1
-someField = 1
A1
-repeatBit = 0
-someField = 3
aFieldAfterA1 = 0
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Unless stated otherwise above:
IBM United Kingdom Limited - Registered in England and Wales with number
741598.
Registered office: PO Box 41, North Harbour, Portsmouth, Hampshire PO6 3AU
