Yes, you treat the terminator as belonging to the sequence.

<xsd:sequence dfdl:separator="some-separator-here” dfdl:separatorSuppressionPolicy="anyEmpty" dfdl:separatorPosition="prefix"
                        dfdl:terminator="some-terminator-here”>
                       <xsd:element name="BodyPart"
                                   dfdl:lengthKind="delimited" minOccurs="1" maxOccurs="unbounded" type="xsd:string" dfdl:occursCountKind="implicit"/>
           </xsd:sequence>

Regards

Steve Hanson
Architect, IBM Data Format Description Language (DFDL)
Co-Chair, OGF DFDL Working Group
IBM SWG, Hursley, UK
smh@uk.ibm.com
tel:+44-1962-815848



From:        "Garriss Jr., James P." <jgarriss@mitre.org>
To:        "dfdl-wg@ogf.org" <dfdl-wg@ogf.org>,
Date:        24/06/2013 18:08
Subject:        [DFDL-WG] Can I specify a terminator for the last element in a        sequence?
Sent by:        dfdl-wg-bounces@ogf.org

---

I have a repeating element, one that can occur 1 to unbounded times.  The elements are separated by a prefixed separator, like so:
 
<xsd:sequence dfdl:separator="some-separator-here” dfdl:separatorSuppressionPolicy="anyEmpty" dfdl:separatorPosition="prefix">
                       <xsd:element name="BodyPart"
                                   dfdl:lengthKind="delimited" minOccurs="1" maxOccurs="unbounded" type="xsd:string" dfdl:occursCountKind="implicit"/>
           </xsd:sequence>
 
The last element (and only the last element) has a terminator.  Is there a way in DFDL to specify that final terminator?--
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