Having thought this through I think that
you are correct. If the content length can never be 0 then EVDP does not
apply. I think IBM DFDL is issuing an error when it should not be.
Regards
Steve Hanson
Architect, IBM
DFDL
Co-Chair, OGF
DFDL Working Group
IBM SWG, Hursley, UK
smh@uk.ibm.com
tel:+44-1962-815848
From:
Mike Beckerle <mbeckerle.dfdl@gmail.com>
To:
Steve Hanson/UK/IBM@IBMGB,
Cc:
"dfdl-wg@ogf.org"
<dfdl-wg@ogf.org>
Date:
09/09/2014 15:37
Subject:
Re: [DFDL-WG]
Catch 22.for EVDP & NVDP ?
Interesting.
To me if lengthKind is explicit, and non-variable (i.e.,
is fixed length), then EVDP doesn't apply, because by definition, such
a representation is not ever empty.
I would assume that EVDP would be ignored in such a case,
and an implementation might even generate warnings if dfdl:emptyValueDelimiterPolicy
appeared directly on such an element or simpleType where a fixed length
is also expressed.
This is one of the challenges that having lengthKind 'explicit'
which handles both the fixed length, and variable-length using an expression,
creates. Even though we don't have a lengthKind 'fixed', we still have
fixed-length as a concept, and some other features interact with fixed
length, like empty values.
Mike Beckerle | OGF DFDL Workgroup Co-Chair | Tresys Technology
| www.tresys.com
Please note: Contributions to the DFDL Workgroup's email
discussions are subject to the OGF
Intellectual Property Policy
On Tue, Sep 2, 2014 at 10:31 AM, Steve Hanson <smh@uk.ibm.com>
wrote:
<xs:element
name="choiceGroup" dfdl:lengthKind="implicit">
<xs:complexType>
<xs:choice dfdl:choiceLengthKind="implicit" dfdl:initiatedContent="yes">
<xs:element name="myNum1"
type="xs:int" dfdl:lengthKind="explicit"
dfdl:length="2"
dfdl:textNumberPattern="#0"
dfdl:initiator="num:"
dfdl:terminator="~"
/>
>
<xs:element name="myText1"
type="xs:string" dfdl:lengthKind="explicit"
dfdl:length="2"
dfdl:initiator="text:"
dfdl:terminator="~"
/>
</xs:choice>
</xs:complexType>
</xs:element>
The above model is a choice of two elements, each of which is fixed length
and has an initiator and terminator. Because the elements are fixed length,
I must set dfdl:emptyValueDelimiterPolicy (EVDP) to be 'none' **.
I also want to discriminate using the initiator, so I set dfdl:initiatedContent
'yes' on the choice, so I must set EVDP to 'initiator' or 'both' ++.
(Same for NVDP if nillable). Catch 22.
** 'none' because the only valid
empty representation is that there is nothing there at all. The element
is fixed length X, so if the delimiters are present then the content must
be length X and can't be zero length.
++ 'initiator' or 'both' because an initiator must always be present
when dfdl:initiatedContent 'yes'.
The implication is that I can't use dfdl:initiatedContent for this choice.
While I can switch off nillable to avoid the error with NVDP, there is
no other way of avoiding the EVDP error.
Regards
Steve Hanson
Architect, IBM
DFDL
Co-Chair, OGF
DFDL Working Group
IBM SWG, Hursley, UK
smh@uk.ibm.com
tel:+44-1962-815848
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